In everyday life and competitive exams like the Delhi Police Constable Examination, you will often encounter numerical expressions that need to be simplified correctly and quickly. Simplification means reducing an expression to its simplest form by performing operations in the right order. Approximation, on the other hand, helps you estimate values when exact calculations are time-consuming or unnecessary.
Mastering simplification and approximation techniques not only improves your accuracy but also boosts your speed-an essential skill during exams. This chapter will guide you through the fundamental rules of simplifying expressions, teach you how to round numbers effectively, and introduce estimation methods that make mental math easier.
By the end of this section, you will be able to:
When you see a mathematical expression with several operations-such as addition, multiplication, division, and brackets-it's important to know the correct order in which to perform these operations. This ensures everyone gets the same answer and avoids confusion.
The rule to remember is called BODMAS or PEMDAS. Both are acronyms that help you recall the order:
Note that multiplication and division have the same priority; so do addition and subtraction. When they appear together, solve them in the order they come from left to right.
graph TD A[Start] --> B[Brackets ( )] B --> C[Orders (powers and roots)] C --> D[Division and Multiplication (left to right)] D --> E[Addition and Subtraction (left to right)] E --> F[Result]
This flowchart shows the stepwise approach to evaluating an expression.
Rounding off is a method of simplifying numbers by reducing the digits while keeping the value close to the original. It is especially useful when dealing with measurements, currency, or when you want a quick estimate.
The basic rule for rounding is:
For example, to round 23.76 to the nearest integer, look at the digit after the decimal point (7). Since 7 ≥ 5, round 23 up to 24.
| Original Number | Rounded to Nearest Integer | Rounded to 1 Decimal Place | Rounded to Nearest Ten |
|---|---|---|---|
| 47.36 | 47 | 47.4 | 50 |
| 123.76 | 124 | 123.8 | 120 |
| 89.44 | 89 | 89.4 | 90 |
Estimation helps you quickly find an approximate answer instead of an exact one. This is useful when you need a fast answer or when exact precision is not necessary.
Here are some common estimation methods:
This number line shows how 4.98 and 3.02 are rounded to 5.00 and 3.00 respectively, making multiplication easier.
Besides following the order of operations, simplifying expressions can be made easier by:
In exams and real life, you will use these skills to:
Step 1: Solve inside the brackets first: \(3 \times 5 = 15\).
Expression becomes: \(8 + 15 - \frac{6}{2}\).
Step 2: Perform division next: \(\frac{6}{2} = 3\).
Expression becomes: \(8 + 15 - 3\).
Step 3: Perform addition and subtraction from left to right:
\(8 + 15 = 23\), then \(23 - 3 = 20\).
Answer: \(20\)
Step 1: To round to the nearest rupee, look at the first digit after the decimal point: 7.
Since 7 ≥ 5, round up: Rs.123.76 rounds to Rs.124.
Step 2: To round to the nearest ten rupees, look at the units digit: 3.
Since 3 < 5, round down: Rs.123.76 rounds to Rs.120.
Answer: Rs.124 (nearest rupee), Rs.120 (nearest ten rupees)
Step 1: Round each number to the nearest thousand:
Step 2: Add the rounded numbers: \(5000 + 3000 + 2000 = 10000\).
Answer: Estimated sum is approximately 10,000.
Step 1: Simplify the innermost bracket: \(3 + 4 = 7\).
Expression becomes: \(5 \times [2 + 7 \times 2] - 10\).
Step 2: Multiply inside the bracket: \(7 \times 2 = 14\).
Expression becomes: \(5 \times [2 + 14] - 10\).
Step 3: Add inside the bracket: \(2 + 14 = 16\).
Expression becomes: \(5 \times 16 - 10\).
Step 4: Multiply: \(5 \times 16 = 80\).
Expression becomes: \(80 - 10\).
Step 5: Subtract: \(80 - 10 = 70\).
Answer: \(70\)
Step 1: Round 4.98 to 5 (nearest whole number).
Round 3.02 to 3 (nearest whole number).
Step 2: Multiply the rounded numbers: \(5 \times 3 = 15\).
Step 3: Since the original numbers are very close to the rounded ones, the estimate is accurate.
Answer: Approximately 15.
When to use: When simplifying any arithmetic expression.
When to use: When approximating values for quick calculations.
When to use: When adding large numbers under time constraints.
When to use: When estimating products mentally.
When to use: When dealing with complex expressions involving multiple operations.
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