Imagine you and your friend are clapping your hands at different intervals. You clap every 4 seconds, and your friend claps every 6 seconds. After how many seconds will you both clap together again?
This question is about finding the Least Common Multiple (LCM) of 4 and 6. The LCM of two or more numbers is the smallest number that is a multiple of all those numbers.
In simple terms, LCM is the smallest number that all the given numbers can divide without leaving a remainder.
Why is LCM important? It helps us solve problems involving synchronization, scheduling, and repeated events. For example, finding when two buses arrive at the same stop together, or when two machines complete their cycles simultaneously.
It is different from the Highest Common Factor (HCF), which is the greatest number that divides two or more numbers exactly. While HCF looks for the biggest common divisor, LCM looks for the smallest common multiple.
Prime factorization means breaking down a number into its prime numbers - numbers that can only be divided by 1 and themselves.
To find the LCM of two or more numbers using prime factorization:
This method ensures you include all prime factors needed to cover each number.
| Number | Prime Factors | Highest Powers for LCM |
|---|---|---|
| 12 | 2² x 3¹ | 2² x 3² |
| 18 | 2¹ x 3² |
Here, for 12 and 18:
This method involves dividing the given numbers by common prime numbers step-by-step until all the numbers become 1.
Steps:
graph TD A[Start with numbers] --> B{Divide by prime factor?} B -->|Yes| C[Divide numbers] C --> D{All numbers 1?} D -->|No| B D -->|Yes| E[Multiply all divisors] E --> F[LCM found]The Highest Common Factor (HCF) and Least Common Multiple (LCM) of two numbers are connected by a simple and useful formula:
This means if you know any two of these three values (a, b, HCF, or LCM), you can find the fourth easily.
Step 1: Find prime factors of each number.
12 = 2 x 2 x 3 = \(2^2 \times 3^1\)
18 = 2 x 3 x 3 = \(2^1 \times 3^2\)
Step 2: Take the highest power of each prime factor.
For 2: highest power is \(2^2\)
For 3: highest power is \(3^2\)
Step 3: Multiply these highest powers.
LCM = \(2^2 \times 3^2 = 4 \times 9 = 36\)
Answer: The LCM of 12 and 18 is 36.
Step 1: Write the numbers side by side:
24, 36, 60
Step 2: Divide by 2 (smallest prime dividing at least one number):
24 / 2 = 12, 36 / 2 = 18, 60 / 2 = 30
Write below: 12, 18, 30
Step 3: Divide again by 2:
12 / 2 = 6, 18 / 2 = 9, 30 / 2 = 15
Write below: 6, 9, 15
Step 4: Divide by 2 again? No, 9 and 15 not divisible by 2.
Divide by 3:
6 / 3 = 2, 9 / 3 = 3, 15 / 3 = 5
Write below: 2, 3, 5
Step 5: Divide by 2:
2 / 2 = 1, 3 / 2 = not divisible, 5 / 2 = not divisible
Write below: 1, 3, 5
Step 6: Divide by 3:
1 / 3 = not divisible, 3 / 3 = 1, 5 / 3 = not divisible
Write below: 1, 1, 5
Step 7: Divide by 5:
1 / 5 = not divisible, 1 / 5 = not divisible, 5 / 5 = 1
Write below: 1, 1, 1
Step 8: Stop as all numbers are 1.
Step 9: Multiply all divisors used: 2 x 2 x 3 x 2 x 3 x 5 = 360
Answer: The LCM of 24, 36, and 60 is 360.
Step 1: Use the formula:
\[ LCM \times HCF = a \times b \]
Step 2: Substitute the values:
\[ LCM \times 5 = 15 \times 20 \]
\[ LCM \times 5 = 300 \]
Step 3: Divide both sides by 5:
\[ LCM = \frac{300}{5} = 60 \]
Answer: The LCM of 15 and 20 is 60.
Prime Factorization Method:
48 = \(2^4 \times 3^1\) (since 48 = 2 x 2 x 2 x 2 x 3)
180 = \(2^2 \times 3^2 \times 5^1\) (180 = 2 x 2 x 3 x 3 x 5)
210 = \(2^1 \times 3^1 \times 5^1 \times 7^1\) (210 = 2 x 3 x 5 x 7)
Take highest powers of all primes:
LCM = \(2^4 \times 3^2 \times 5 \times 7 = 16 \times 9 \times 5 \times 7\)
Calculate stepwise:
16 x 9 = 144
144 x 5 = 720
720 x 7 = 5040
LCM = 5040
Verification by Division Method:
Start with 48, 180, 210
Divide by 2: 24, 90, 105
Divide by 2: 12, 45, 105 (105 not divisible by 2, so only divide those divisible)
Divide by 2: 6, 45, 105
Divide by 2: 3, 45, 105
Divide by 3: 1, 15, 35
Divide by 3: 1, 5, 35
Divide by 5: 1, 1, 7
Divide by 7: 1, 1, 1
Multiply divisors: 2 x 2 x 2 x 2 x 3 x 3 x 5 x 7 = 5040
Answer: The LCM of 48, 180, and 210 is 5040.
Step 1: Find the LCM of 15 and 20 to know when they will arrive together again.
Prime factors:
15 = 3 x 5
20 = 2² x 5
LCM = 2² x 3 x 5 = 4 x 3 x 5 = 60
They will arrive together every 60 minutes.
Step 2: Since they arrived together at 10:00 AM, next time will be 10:00 AM + 60 minutes = 11:00 AM.
Step 3: To pay for both fares an equal number of times, find the LCM of the fares Rs.30 and Rs.50.
Prime factors:
30 = 2 x 3 x 5
50 = 2 x 5²
LCM = 2 x 3 x 5² = 2 x 3 x 25 = 150
Answer: You need to carry at least Rs.150 to pay for both fares an equal number of times.
When to use: When dealing with two or three numbers, choose the method based on simplicity.
When to use: When HCF is known or easier to find, use it to quickly calculate LCM.
When to use: During prime factorization to ensure accuracy.
When to use: When performing division method to quickly reduce numbers.
When to use: In word problems involving repeated cycles or intervals.
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