The number system is the foundation of all quantitative aptitude topics. It is a structured way to represent and work with numbers, which are essential in everyday calculations, problem solving, and competitive exams. Understanding the different types of numbers, their properties, and how they interact through operations is crucial for solving a wide range of problems efficiently.
In this section, we will explore the various types of numbers, their unique properties, and how to perform basic operations on them. We will also see how these concepts apply in real-world contexts such as currency calculations in INR and measurements in metric units. By mastering the number system, you will build a strong base for more advanced topics like percentages, ratios, and interest calculations.
Numbers come in different forms, each with specific characteristics and uses. Let's define and understand the main types of numbers used in quantitative aptitude.
Numbers have special properties that help us classify and work with them more effectively. Let's explore some key properties.
An even number is any integer divisible by 2 without a remainder. Examples: 2, 4, 6, 100.
An odd number is any integer that leaves a remainder of 1 when divided by 2. Examples: 1, 3, 5, 99.
Knowing whether a number is even or odd helps in simplifying calculations and solving problems quickly.
A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself. Examples: 2, 3, 5, 7, 11.
A composite number is a natural number greater than 1 that has more than two positive divisors. Examples: 4, 6, 8, 9, 12.
Prime numbers are the building blocks of all natural numbers through multiplication (prime factorization).
Divisibility rules are shortcuts to quickly check if a number is divisible by another without performing full division. Here is a summary of common rules:
| Divisor | Rule | Example |
|---|---|---|
| 2 | Number ends with 0, 2, 4, 6, or 8 | 124 is divisible by 2 |
| 3 | Sum of digits divisible by 3 | 123 (1+2+3=6) divisible by 3 |
| 5 | Number ends with 0 or 5 | 145 ends with 5 |
| 9 | Sum of digits divisible by 9 | 729 (7+2+9=18) divisible by 9 |
| 10 | Number ends with 0 | 230 ends with 0 |
Basic arithmetic operations-addition, subtraction, multiplication, and division-are the tools we use to manipulate numbers. Understanding these operations and their properties is essential for problem solving.
A factor of a number is an integer that divides it exactly without leaving a remainder. For example, factors of 12 are 1, 2, 3, 4, 6, and 12.
A multiple of a number is the product of that number and any integer. For example, multiples of 5 include 5, 10, 15, 20, and so on.
The Highest Common Factor (HCF) of two numbers is the largest number that divides both of them exactly.
The Least Common Multiple (LCM) of two numbers is the smallest number that is a multiple of both.
These concepts are vital for solving problems involving fractions, ratios, and scheduling.
graph TD A[Start with two numbers a and b] --> B[Find prime factorization of a and b] B --> C[Identify common prime factors with minimum exponents] C --> D[Multiply these to get HCF] B --> E[Identify all prime factors with maximum exponents] E --> F[Multiply these to get LCM] D --> G[End] F --> G
Step 1: Find the prime factorization of each number.
36 = \(2^2 \times 3^2\)
48 = \(2^4 \times 3^1\)
Step 2: For HCF, take the minimum exponent of each prime factor.
HCF = \(2^{\min(2,4)} \times 3^{\min(2,1)} = 2^2 \times 3^1 = 4 \times 3 = 12\)
Step 3: For LCM, take the maximum exponent of each prime factor.
LCM = \(2^{\max(2,4)} \times 3^{\max(2,1)} = 2^4 \times 3^2 = 16 \times 9 = 144\)
Answer: HCF = 12, LCM = 144
Step 1: Recall that \(\sqrt{2}\) is the square root of 2.
Step 2: \(\sqrt{2}\) cannot be expressed as a fraction of two integers.
Step 3: Its decimal expansion is non-terminating and non-repeating (approximately 1.4142135...).
Step 4: Therefore, \(\sqrt{2}\) is an irrational number.
Step 5: Since irrational numbers are part of real numbers, \(\sqrt{2}\) is also a real number.
Answer: \(\sqrt{2}\) is an irrational and real number, but not rational or integer.
Step 1: Check divisibility by 3.
Sum of digits = 1 + 2 + 3 + 4 + 5 = 15
Since 15 is divisible by 3, 12345 is divisible by 3.
Step 2: Check divisibility by 5.
The last digit is 5, so 12345 is divisible by 5.
Answer: 12345 is divisible by both 3 and 5.
Step 1: Start at -7 on the number line.
Step 2: Since we are adding +12, move 12 units to the right.
Step 3: Moving 12 units right from -7 lands on 5.
Answer: \(-7 + 12 = 5\)
Step 1: Understand that 15% means 15 per 100, or \(\frac{15}{100}\).
Step 2: Multiply 2000 by \(\frac{15}{100}\) to find 15% of 2000.
\(2000 \times \frac{15}{100} = 2000 \times 0.15 = 300\)
Answer: 15% of INR 2000 is INR 300.
When to use: When checking if large numbers are divisible by small primes like 2, 3, 5, or 9.
When to use: When either HCF or LCM is missing in a problem.
When to use: When adding or subtracting positive and negative integers.
When to use: When finding HCF, LCM or simplifying fractions.
When to use: When dealing with rational, irrational, or integer numbers in problems.
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