In mathematics, especially in number theory, divisibility is a fundamental concept that helps us understand when one number can be divided by another without leaving a remainder. For example, 12 is divisible by 3 because 12 / 3 = 4 exactly, with no remainder.
Why is this important? In competitive exams and problem-solving, quickly determining whether a number is divisible by another saves time and effort. Instead of performing long division, you can use simple rules to check divisibility instantly. These rules are especially useful when dealing with large numbers or simplifying fractions.
This chapter will guide you through the most common divisibility rules, starting from the simplest and moving to more complex ones. You will learn how to apply these rules, understand their reasoning, and use them in real-life contexts such as dividing money or measuring quantities.
Let's begin with the divisibility rules for some of the most frequently encountered numbers: 2, 3, 5, 9, and 10. These rules rely on patterns in the digits of a number, making them easy to remember and apply.
| Divisor | Divisibility Rule | Example |
|---|---|---|
| 2 | The last digit is even (0, 2, 4, 6, 8) | 124 (last digit 4) is divisible by 2 |
| 3 | The sum of all digits is divisible by 3 | 123 (1+2+3=6; 6 divisible by 3) is divisible by 3 |
| 5 | The last digit is 0 or 5 | 145 (last digit 5) is divisible by 5 |
| 9 | The sum of all digits is divisible by 9 | 729 (7+2+9=18; 18 divisible by 9) is divisible by 9 |
| 10 | The last digit is 0 | 230 (last digit 0) is divisible by 10 |
Why do these rules work? For 2 and 5, the last digit determines divisibility because of the base-10 number system. For 3 and 9, the sum of digits rule works because 10 ≡ 1 (mod 3 or 9), so each digit contributes its face value modulo 3 or 9.
Next, we explore divisibility rules for 4, 6, and 8. These are slightly more involved but still rely on patterns in the digits.
| Divisor | Divisibility Rule | Example |
|---|---|---|
| 4 | The number formed by the last two digits is divisible by 4 | 312 (last two digits 12; 12 / 4 = 3) is divisible by 4 |
| 6 | The number is divisible by both 2 and 3 | 114 (even and sum digits 1+1+4=6 divisible by 3) is divisible by 6 |
| 8 | The number formed by the last three digits is divisible by 8 | 5,136 (last three digits 136; 136 / 8 = 17) is divisible by 8 |
Notice how the rules for 4 and 8 focus on the last two or three digits. This is because powers of 10 (like 100 or 1000) are divisible by 4 and 8 respectively, so only the last digits affect divisibility.
Divisibility rules for 7, 11, and 13 are less straightforward but can be mastered with practice. These rules often involve a process of subtraction or addition of parts of the number.
To check if a number is divisible by 7:
graph TD A[Start with number N] --> B[Separate last digit d] B --> C[Double d to get 2d] C --> D[Subtract 2d from remaining number] D --> E{Is result divisible by 7?} E -->|Yes| F[Original number divisible by 7] E -->|No| G[Repeat process with new number]Sum the digits in odd positions and the digits in even positions separately. If the difference between these two sums is divisible by 11 (including 0), then the number is divisible by 11.
A similar method to 7 can be used: multiply the last digit by 4 and add it to the remaining leading number. Repeat until a small number is obtained. If that number is divisible by 13, so is the original.
Understanding prime factorization helps us see why divisibility rules work and how to check divisibility for composite numbers.
Prime factorization is expressing a number as a product of prime numbers. For example, 12 = 2 x 2 x 3.
If a number is divisible by another, it must contain all the prime factors of that number.
Here, 60 is factorized into 6 and 10, which further break down into primes 2, 3, 2, and 5. To check if a number is divisible by 60, it must be divisible by 2, 3, and 5 in the correct powers.
Step 1: Sum the digits: 1 + 2 + 3 + 4 + 5 + 6 = 21
Step 2: Check divisibility by 3: 21 / 3 = 7 (no remainder), so 123456 is divisible by 3.
Step 3: Check divisibility by 9: 21 / 9 = 2 remainder 3, so 21 is not divisible by 9.
Answer: 123456 is divisible by 3 but not by 9.
Step 1: Separate last digit: 3
Step 2: Double it: 3 x 2 = 6
Step 3: Subtract from remaining number: 20 - 6 = 14
Step 4: Check if 14 is divisible by 7: 14 / 7 = 2 (no remainder)
Answer: 203 is divisible by 7.
Step 1: Sum digits in odd positions (from right): 8 (1st) + 7 (3rd) = 15
Step 2: Sum digits in even positions: 2 (2nd) + 2 (4th) = 4
Step 3: Find difference: 15 - 4 = 11
Step 4: Since 11 is divisible by 11, 2728 is divisible by 11.
Answer: 2728 is divisible by 11.
Step 1: Prime factorize 12: 12 = 2 x 2 x 3
Step 2: Prime factorize 144: 144 = 2 x 2 x 2 x 2 x 3 x 3
Step 3: Since 144 contains at least two 2s and one 3, it is divisible by 12.
Answer: 144 is divisible by 12.
Step 1: Sum the digits of 123456: 1 + 2 + 3 + 4 + 5 + 6 = 21
Step 2: Check if 21 is divisible by 9: 21 / 9 = 2 remainder 3, so no.
Step 3: Check if 21 is divisible by 3: 21 / 3 = 7, yes.
Step 4: Since 9 requires divisibility by 9, the amount cannot be evenly divided among 9 people.
Answer: INR 123456 cannot be evenly divided among 9 people.
When to use: Quickly check divisibility without performing full division.
When to use: Instantly determine divisibility by these numbers by looking at the last digit.
When to use: Efficiently test divisibility by 7 without long division.
When to use: Quickly check divisibility by 11, especially for large numbers.
When to use: Check divisibility by verifying divisibility by their prime factors.
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