👁 Preview — Study, Practice and Revise are open; mock tests and the rest of the syllabus unlock on subscription. Unlock all · ₹4,999
← Back to Number System
Study mode

Divisibility Rules

Introduction to Divisibility Rules

In mathematics, especially in number theory, divisibility is a fundamental concept that helps us understand when one number can be divided by another without leaving a remainder. For example, 12 is divisible by 3 because 12 / 3 = 4 exactly, with no remainder.

Why is this important? In competitive exams and problem-solving, quickly determining whether a number is divisible by another saves time and effort. Instead of performing long division, you can use simple rules to check divisibility instantly. These rules are especially useful when dealing with large numbers or simplifying fractions.

This chapter will guide you through the most common divisibility rules, starting from the simplest and moving to more complex ones. You will learn how to apply these rules, understand their reasoning, and use them in real-life contexts such as dividing money or measuring quantities.

Basic Divisibility Rules

Let's begin with the divisibility rules for some of the most frequently encountered numbers: 2, 3, 5, 9, and 10. These rules rely on patterns in the digits of a number, making them easy to remember and apply.

Divisor Divisibility Rule Example
2 The last digit is even (0, 2, 4, 6, 8) 124 (last digit 4) is divisible by 2
3 The sum of all digits is divisible by 3 123 (1+2+3=6; 6 divisible by 3) is divisible by 3
5 The last digit is 0 or 5 145 (last digit 5) is divisible by 5
9 The sum of all digits is divisible by 9 729 (7+2+9=18; 18 divisible by 9) is divisible by 9
10 The last digit is 0 230 (last digit 0) is divisible by 10

Why do these rules work? For 2 and 5, the last digit determines divisibility because of the base-10 number system. For 3 and 9, the sum of digits rule works because 10 ≡ 1 (mod 3 or 9), so each digit contributes its face value modulo 3 or 9.

Divisibility Rules for 4, 6, and 8

Next, we explore divisibility rules for 4, 6, and 8. These are slightly more involved but still rely on patterns in the digits.

Divisor Divisibility Rule Example
4 The number formed by the last two digits is divisible by 4 312 (last two digits 12; 12 / 4 = 3) is divisible by 4
6 The number is divisible by both 2 and 3 114 (even and sum digits 1+1+4=6 divisible by 3) is divisible by 6
8 The number formed by the last three digits is divisible by 8 5,136 (last three digits 136; 136 / 8 = 17) is divisible by 8

Notice how the rules for 4 and 8 focus on the last two or three digits. This is because powers of 10 (like 100 or 1000) are divisible by 4 and 8 respectively, so only the last digits affect divisibility.

Divisibility Rules for 7, 11, and 13

Divisibility rules for 7, 11, and 13 are less straightforward but can be mastered with practice. These rules often involve a process of subtraction or addition of parts of the number.

Divisibility by 7 (Doubling and Subtracting Method)

To check if a number is divisible by 7:

  1. Take the last digit of the number.
  2. Double it.
  3. Subtract this doubled value from the remaining leading part of the number.
  4. If the result is divisible by 7 (including 0), then the original number is divisible by 7.
  5. If not, repeat the process with the new number.
graph TD    A[Start with number N] --> B[Separate last digit d]    B --> C[Double d to get 2d]    C --> D[Subtract 2d from remaining number]    D --> E{Is result divisible by 7?}    E -->|Yes| F[Original number divisible by 7]    E -->|No| G[Repeat process with new number]

Divisibility by 11 (Alternating Sum Method)

Sum the digits in odd positions and the digits in even positions separately. If the difference between these two sums is divisible by 11 (including 0), then the number is divisible by 11.

Divisibility by 13

A similar method to 7 can be used: multiply the last digit by 4 and add it to the remaining leading number. Repeat until a small number is obtained. If that number is divisible by 13, so is the original.

Prime Factorization and Divisibility

Understanding prime factorization helps us see why divisibility rules work and how to check divisibility for composite numbers.

Prime factorization is expressing a number as a product of prime numbers. For example, 12 = 2 x 2 x 3.

If a number is divisible by another, it must contain all the prime factors of that number.

60 6 10 2 3 2 5

Here, 60 is factorized into 6 and 10, which further break down into primes 2, 3, 2, and 5. To check if a number is divisible by 60, it must be divisible by 2, 3, and 5 in the correct powers.

Worked Examples

Example 1: Divisibility by 3 and 9 Easy
Check if the number 123456 is divisible by 3 and 9.

Step 1: Sum the digits: 1 + 2 + 3 + 4 + 5 + 6 = 21

Step 2: Check divisibility by 3: 21 / 3 = 7 (no remainder), so 123456 is divisible by 3.

Step 3: Check divisibility by 9: 21 / 9 = 2 remainder 3, so 21 is not divisible by 9.

Answer: 123456 is divisible by 3 but not by 9.

Example 2: Divisibility by 7 Using Doubling Method Medium
Check if 203 is divisible by 7 using the doubling and subtraction method.

Step 1: Separate last digit: 3

Step 2: Double it: 3 x 2 = 6

Step 3: Subtract from remaining number: 20 - 6 = 14

Step 4: Check if 14 is divisible by 7: 14 / 7 = 2 (no remainder)

Answer: 203 is divisible by 7.

Example 3: Divisibility by 11 Using Alternating Sum Medium
Check if 2728 is divisible by 11.

Step 1: Sum digits in odd positions (from right): 8 (1st) + 7 (3rd) = 15

Step 2: Sum digits in even positions: 2 (2nd) + 2 (4th) = 4

Step 3: Find difference: 15 - 4 = 11

Step 4: Since 11 is divisible by 11, 2728 is divisible by 11.

Answer: 2728 is divisible by 11.

Example 4: Divisibility by 12 Using Prime Factorization Medium
Check if 144 is divisible by 12 using prime factorization.

Step 1: Prime factorize 12: 12 = 2 x 2 x 3

Step 2: Prime factorize 144: 144 = 2 x 2 x 2 x 2 x 3 x 3

Step 3: Since 144 contains at least two 2s and one 3, it is divisible by 12.

Answer: 144 is divisible by 12.

Example 5: Real-Life Divisibility Application Easy
Can INR 123456 be evenly divided among 9 people?

Step 1: Sum the digits of 123456: 1 + 2 + 3 + 4 + 5 + 6 = 21

Step 2: Check if 21 is divisible by 9: 21 / 9 = 2 remainder 3, so no.

Step 3: Check if 21 is divisible by 3: 21 / 3 = 7, yes.

Step 4: Since 9 requires divisibility by 9, the amount cannot be evenly divided among 9 people.

Answer: INR 123456 cannot be evenly divided among 9 people.

Divisibility by 2

Last\ digit\ is\ even

A number is divisible by 2 if its last digit is 0, 2, 4, 6, or 8

N = number

Divisibility by 3

\[\text{Sum of digits of } N \equiv 0 \pmod{3}\]

A number is divisible by 3 if the sum of its digits is divisible by 3

N = number

Divisibility by 5

\[Last\ digit = 0 \text{ or } 5\]

A number is divisible by 5 if its last digit is 0 or 5

N = number

Divisibility by 9

\[\text{Sum of digits of } N \equiv 0 \pmod{9}\]

A number is divisible by 9 if the sum of its digits is divisible by 9

N = number

Divisibility by 10

Last\ digit = 0

A number is divisible by 10 if its last digit is 0

N = number

Divisibility by 4

\[Last\ two\ digits\ of\ N \equiv 0 \pmod{4}\]

A number is divisible by 4 if the number formed by its last two digits is divisible by 4

N = number

Divisibility by 6

\[N \equiv 0 \pmod{2} \text{ and } N \equiv 0 \pmod{3}\]

A number is divisible by 6 if it is divisible by both 2 and 3

N = number

Divisibility by 8

\[Last\ three\ digits\ of\ N \equiv 0 \pmod{8}\]

A number is divisible by 8 if the number formed by its last three digits is divisible by 8

N = number

Divisibility by 11

\[\left(\sum_{odd} digits - \sum_{even} digits\right) \equiv 0 \pmod{11}\]

A number is divisible by 11 if the difference between the sum of digits in odd and even positions is divisible by 11

N = number

Tips & Tricks

Tip: Use the sum of digits shortcut for divisibility by 3 and 9.

When to use: Quickly check divisibility without performing full division.

Tip: Check the last digit for divisibility by 2 and 5.

When to use: Instantly determine divisibility by these numbers by looking at the last digit.

Tip: Use the doubling and subtracting method for divisibility by 7.

When to use: Efficiently test divisibility by 7 without long division.

Tip: Apply the alternating sum method for divisibility by 11.

When to use: Quickly check divisibility by 11, especially for large numbers.

Tip: Combine rules for composite numbers like 6 and 12.

When to use: Check divisibility by verifying divisibility by their prime factors.

Common Mistakes to Avoid

❌ Checking divisibility by 3 or 9 without summing all digits.
✓ Always sum all digits completely before deciding.
Why: Partial sums can lead to incorrect conclusions.
❌ Confusing divisibility by 4 with divisibility by 2.
✓ Remember divisibility by 4 depends on the last two digits, not just the last digit.
Why: The rule for 4 is more restrictive than for 2.
❌ Applying divisibility rule for 5 to numbers ending with digits other than 0 or 5.
✓ Only numbers ending with 0 or 5 are divisible by 5.
Why: Misapplication leads to false positives.
❌ Forgetting to check both conditions for divisibility by 6.
✓ Check divisibility by 2 and 3 separately before concluding divisibility by 6.
Why: 6 is composite; both conditions must hold.
❌ Incorrectly calculating alternating sums for 11.
✓ Carefully sum digits in odd and even positions separately.
Why: Misplacement of digits can cause wrong results.
Curated videos per subtopic
Top YouTube explainers, AI-ranked for your exam and language. Unlocks with subscription.
Unlock

Try Practice next.

Progress tracking is paywalled — subscribe to mark subtopics as understood and save your streak.

Go to practice →
Ask a doubt
Divisibility Rules · 10 free messages
Ask me anything about this subtopic. You have 10 free messages this session — chat history isn't saved in preview.