Numbers are the foundation of mathematics and appear everywhere in daily life-from counting objects to measuring distances. Understanding the number system helps us classify and work with different types of numbers effectively. Alongside this, concepts like factors, multiples, Highest Common Factor (HCF), and Least Common Multiple (LCM) are essential tools that help solve many practical problems such as scheduling, dividing things equally, and simplifying calculations.
In this chapter, we will explore the various types of numbers, learn how to identify factors and multiples, and master the methods to find HCF and LCM. These concepts are not only important for competitive exams but also for building a strong mathematical foundation.
Let's start by understanding the different types of numbers and how they relate to each other.
Here is a hierarchical view of the number system:
Natural Numbers (N): These are the counting numbers starting from 1, 2, 3, and so on.
Whole Numbers (W): Natural numbers including zero: 0, 1, 2, 3, ...
Integers (Z): Whole numbers along with their negative counterparts: ..., -3, -2, -1, 0, 1, 2, 3, ...
Rational Numbers (Q): Numbers that can be expressed as a fraction \(\frac{p}{q}\) where \(p\) and \(q\) are integers and \(q eq 0\). Examples: \(\frac{1}{2}, -\frac{3}{4}, 5\).
Irrational Numbers: Numbers that cannot be expressed as fractions, their decimal expansions are non-terminating and non-repeating. Examples: \(\sqrt{2}, \pi\).
Divisibility rules help us quickly determine if one number is divisible by another without performing full division. This is very useful for factorization and simplifying problems.
A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself. Examples: 2, 3, 5, 7, 11, 13, ...
A composite number is a natural number greater than 1 that is not prime; it has factors other than 1 and itself.
Prime factorization means expressing a number as a product of its prime factors. This is a key step in finding HCF and LCM.
Let's see how to perform prime factorization using a factor tree:
Explanation: Start with 84. It can be divided into 12 and 7 (since \(12 \times 7 = 84\)). Then break 12 into 2 and 6. Finally, break 6 into 2 and 3. All the leaves of the tree (2, 2, 3, 7) are prime numbers.
So, the prime factorization of 84 is:
\[ 84 = 2 \times 2 \times 3 \times 7 = 2^2 \times 3 \times 7 \]
The Highest Common Factor (HCF) of two or more numbers is the largest number that divides all of them exactly (without leaving a remainder). It is also called the Greatest Common Divisor (GCD).
Why is HCF important? It helps in simplifying fractions, dividing things into equal parts, and solving problems involving common factors.
Write down all factors of each number and find the greatest one common to all.
Find prime factors of each number, then multiply the common prime factors with the smallest powers.
This is an efficient method based on the principle that the HCF of two numbers also divides their difference.
graph TD A[Start with numbers a and b, where a > b] A --> B[Divide a by b] B --> C[Find remainder r] C --> D{Is r = 0?} D -- No --> E[Set a = b, b = r] E --> B D -- Yes --> F[HCF is b]This process repeats until the remainder is zero. The divisor at that point is the HCF.
The Least Common Multiple (LCM) of two or more numbers is the smallest number that is a multiple of all of them.
LCM is useful in problems involving synchronization of events, adding fractions, and finding common denominators.
Find prime factors of each number. For each prime factor, take the highest power that appears in any number and multiply them.
| Prime Factor | 12 = \(2^2 \times 3\) | 18 = \(2 \times 3^2\) | Highest Power for LCM |
|---|---|---|---|
| 2 | 22 | 21 | 22 |
| 3 | 31 | 32 | 32 |
So, \(\text{LCM} = 2^2 \times 3^2 = 4 \times 9 = 36\).
There is a useful relationship between HCF and LCM:
Step 1: Find prime factors of 36.
36 = 2 x 2 x 3 x 3 = \(2^2 \times 3^2\)
Step 2: Find prime factors of 48.
48 = 2 x 2 x 2 x 2 x 3 = \(2^4 \times 3^1\)
Step 3: For HCF, take the lowest powers of common primes.
HCF = \(2^{\min(2,4)} \times 3^{\min(2,1)} = 2^2 \times 3^1 = 4 \times 3 = 12\)
Step 4: For LCM, take the highest powers of all primes.
LCM = \(2^{\max(2,4)} \times 3^{\max(2,1)} = 2^4 \times 3^2 = 16 \times 9 = 144\)
Answer: HCF = 12, LCM = 144
Step 1: Divide 270 by 192.
270 / 192 = 1 remainder 78 (since 270 = 192 x 1 + 78)
Step 2: Now divide 192 by 78.
192 / 78 = 2 remainder 36 (192 = 78 x 2 + 36)
Step 3: Divide 78 by 36.
78 / 36 = 2 remainder 6 (78 = 36 x 2 + 6)
Step 4: Divide 36 by 6.
36 / 6 = 6 remainder 0 (36 = 6 x 6 + 0)
Step 5: Since remainder is 0, HCF is the divisor 6.
Answer: HCF(270, 192) = 6
Step 1: Identify the intervals: 12 minutes and 18 minutes.
Step 2: Find LCM of 12 and 18.
Prime factors:
LCM = \(2^{\max(2,1)} \times 3^{\max(1,2)} = 2^2 \times 3^2 = 4 \times 9 = 36\)
Answer: Both buses will return together after 36 minutes.
Step 1: Use the formula:
\[ \text{HCF} \times \text{LCM} = \text{Product of numbers} \]
Step 2: Substitute the values:
\[ 6 \times \text{LCM} = 24 \times 90 \]
\[ 6 \times \text{LCM} = 2160 \]
Step 3: Solve for LCM:
\[ \text{LCM} = \frac{2160}{6} = 360 \]
Answer: LCM of 24 and 90 is 360.
Step 1: Let the third number be \(x\).
Step 2: Since HCF is 5, express numbers as multiples of 5:
25 = 5 x 5, 60 = 5 x 12, \(x = 5 \times k\)
Step 3: Find LCM of the three numbers:
LCM(25, 60, \(x\)) = 600
Divide all numbers by 5 to simplify:
5, 12, \(k\)
LCM(5, 12, \(k\)) = \(\frac{600}{5} = 120\)
Step 4: Find LCM of 5 and 12:
Prime factors:
LCM(5, 12) = \(2^2 \times 3 \times 5 = 60\)
Step 5: Since LCM(5,12,k) = 120, and LCM(5,12) = 60, \(k\) must introduce a factor to increase LCM to 120.
120 / 60 = 2, so \(k\) must have factor 2.
Step 6: \(k\) must be a multiple of 2 but not introduce factors that reduce HCF.
Try \(k = 2\).
Step 7: Third number \(x = 5 \times 2 = 10\).
Answer: The third number is 10.
When to use: When numbers are not too large and factorization is straightforward.
When to use: For large numbers where factorization is time-consuming.
When to use: When either HCF or LCM is missing but the other and the numbers are known.
When to use: Problems involving periodic events or cycles.
When to use: At the start of factorization or when simplifying numbers.
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