In everyday life, we often need to summarize a set of numbers to understand them better. For example, when you want to know the average marks scored by students in a class or the average age of members in a family, you use the concept of averages. The average gives a single value that represents the entire group, making it easier to compare and analyze data.
In this chapter, we will explore how to calculate averages, especially the mean, and apply these concepts to solve problems related to ages. Age-related problems are common in competitive exams and require logical thinking and equation formation skills. We will use examples based on the metric system and Indian Rupees (INR) to keep the context familiar and practical.
The most commonly used average is the mean. The mean is calculated by adding all the values in a set and then dividing by the number of values. This gives a central value that represents the data.
Besides the mean, there are other types of averages like median (the middle value when data is arranged in order) and mode (the most frequently occurring value). However, for most aptitude problems, the mean is the primary focus.
| Values | Sum of Values | Number of Values | Average (Mean) |
|---|---|---|---|
| 12, 15, 18, 20, 25 | 12 + 15 + 18 + 20 + 25 = 90 | 5 | 90 / 5 = 18 |
Mathematically, the formula for average is:
Age problems often involve groups of people whose average age changes when individuals are added or removed, or when time passes. Understanding how to relate the average age to the total sum of ages is key to solving these problems.
Since average age is the total sum of ages divided by the number of people, we can write:
When the average age changes due to addition or removal of members, or after some years, we can form equations using this relationship to find unknown ages or averages.
graph TD A[Understand the Problem] --> B[Define Variables] B --> C[Form Equations Using Average and Sum] C --> D[Solve Equations] D --> E[Verify the Solution]
Step 1: Add all the numbers: 12 + 15 + 18 + 20 + 25 = 90.
Step 2: Count the number of values: 5.
Step 3: Calculate the average using the formula:
\( \text{Average} = \frac{90}{5} = 18 \)
Answer: The average of the numbers is 18.
Step 1: Calculate the total age of 10 people:
\( \text{Total age} = 25 \times 10 = 250 \) years.
Step 2: Calculate the total age of remaining 9 people:
\( \text{New total age} = 24 \times 9 = 216 \) years.
Step 3: Find the age of the person who left:
\( \text{Age of removed person} = 250 - 216 = 34 \) years.
Answer: The person who left was 34 years old.
Step 1: Calculate total age of original 15 students:
\( 14 \times 15 = 210 \) years.
Step 2: Calculate total age of 5 new students:
\( 16 \times 5 = 80 \) years.
Step 3: Calculate combined total age:
\( 210 + 80 = 290 \) years.
Step 4: Calculate new total number of students:
\( 15 + 5 = 20 \).
Step 5: Calculate new average age:
\( \frac{290}{20} = 14.5 \) years.
Answer: The new average age is 14.5 years.
Step 1: Calculate total current age:
\( 20 \times 5 = 100 \) years.
Step 2: Calculate total age after 5 years:
\( 25 \times 5 = 125 \) years.
Step 3: Find the total increase in ages:
\( 125 - 100 = 25 \) years.
Step 4: Verify that each person's age increased by 5 years, so total increase should be \( 5 \times 5 = 25 \) years, which matches.
Answer: The total increase in their ages is 25 years.
Step 1: Calculate total age of Group A:
\( 10 \times 22 = 220 \) years.
Step 2: Calculate total age of Group B:
\( 15 \times 28 = 420 \) years.
Step 3: Calculate combined total age:
\( 220 + 420 = 640 \) years.
Step 4: Calculate total number of people:
\( 10 + 15 = 25 \).
Step 5: Calculate combined average age:
\( \frac{640}{25} = 25.6 \) years.
Answer: The combined average age is 25.6 years.
When to use: When multiple average calculations involve adding or removing members.
When to use: In age problems involving multiple unknowns.
When to use: When problems mention ages after or before a certain number of years.
When to use: When merging groups or data sets with different average values.
When to use: In problems mixing ages with monetary values or measurements.
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