In everyday life, we often want to summarize a collection of numbers by a single number that best represents them. This "middle value" or typical value is called Average. Imagine you have marks scored by five students in a test - instead of remembering all five scores, you can calculate their average to get a sense of their overall performance.
The average helps in understanding patterns and making comparisons. For example, you might want to know your average monthly expense, average speed during a trip, or average rainfall in a month. In all such scenarios, average tells us about the general trend of data rather than individual details.
Formally, average is a measure of central tendency, which means it indicates the center or typical value of a data set.
The most common type of average is the Arithmetic Mean. This is simply the sum of all values divided by the total number of values.
Mathematically, if you have numbers \( x_1, x_2, x_3, \ldots, x_n \), their arithmetic mean (average) is:
Example: Find the average of 4, 7, 10, 15, and 20.
So, the average is 11.2.
Sometimes, certain values are more important or occur more frequently than others. In such cases, the simple average does not tell the whole story. Instead, we use a Weighted Average, where each value is multiplied by its weight or frequency before averaging.
For example, suppose a student scores 80 marks in a test worth 30% of the final grade, and 90 marks in a test worth 70%. The final average won't be simply the mean of 80 and 90, but weighted by the respective percentages.
The formula is:
Consider the following table:
| Value (Marks) | Weight (Percentage %) | Weighted Contribution |
|---|---|---|
| 80 | 30 | 80 x 30 = 2400 |
| 90 | 70 | 90 x 70 = 6300 |
| Total | 8700 | |
Calculate weighted average:
\[\text{Weighted Average} = \frac{2400 + 6300}{30 + 70} = \frac{8700}{100} = 87\]
The final average score is 87, reflecting the importance of each test.
In exams and real scenarios, data sets can change. You may add new values or remove some. How does this affect the average?
Let's understand these effects using the total sum concept.
If the original average is \( \bar{x} \) with \( n \) values, then total sum is:
\[\text{Total Sum} = \bar{x} \times n\]
Now, if a new value \( a \) is added, the new average \( \bar{x}_{new} \) is:
If a value \( r \) is removed, new average becomes:
graph TD A[Start: Known Average and Count] --> B[Calculate total sum: Average x Count] B --> C{Data Added or Removed?} C -->|Added| D[New Total = Old Total + New Value] C -->|Removed| E[New Total = Old Total - Removed Value] D --> F[New Count = Old Count + 1] E --> G[New Count = Old Count - 1] F --> H[New Average = New Total / New Count] G --> H H --> I[End: Updated Average Known]Step 1: Add all marks: \(65 + 70 + 75 + 80 + 85 = 375\).
Step 2: Total number of subjects = 5.
Step 3: Use formula: Average = Sum / Number = \( \frac{375}{5} = 75 \).
Answer: The average marks scored by the student are 75.
Step 1: Multiply scores by their weights:
Step 2: Add weighted scores: 2880 + 5280 = 8160.
Step 3: Add weights: 40 + 60 = 100.
Step 4: Calculate weighted average:
\[ \frac{8160}{100} = 81.6 \]
Answer: The final weighted average score is 81.6.
Step 1: Calculate total production for 10 days: \(500 \times 10 = 5000\) units.
Step 2: Add production of 11th day: \(5000 + 550 = 5550\) units in total.
Step 3: New count of days: 11.
Step 4: New average:
\[ \frac{5550}{11} = 504.55 \]
Answer: The new average production per day is approximately 504.55 units.
Step 1: Calculate the total weight of original 8 students:
\(55 \times 8 = 440\) kg.
Step 2: Calculate the total weight of new group of 8 students:
New average x number = \(56.5 \times 8 = 452\) kg.
Step 3: Weight of new two students = \(60 + 65 = 125\) kg.
Step 4: Let the total weight of two students who left be \(w\).
Since replacing them causes the total to increase from 440 to 452,
New total = Old total - \(w\) + 125 = 452
\(440 - w + 125 = 452\)
\(565 - w = 452\)
\(w = 565 - 452 = 113\) kg.
Step 5: Average weight of two who left = \( \frac{113}{2} = 56.5 \) kg.
Answer: The average weight of the two students who left is 56.5 kg.
Step 1: Calculate total marks of each class:
Step 2: Add total marks: \(2100 + 1600 = 3700\) marks.
Step 3: Add total students: \(30 + 20 = 50\).
Step 4: Calculate combined average:
\[ \frac{3700}{50} = 74 \]
Answer: The combined average mark is 74.
When to use: To avoid recalculating the sum from raw data, especially in replacement or addition problems.
When to use: When dealing with data sets with varying importance like marks with different max scores or stocks with different quantities.
When to use: In problems asking for new averages after data changes.
When to use: When combining two groups or sets with known averages and counts.
When to use: When multiple choice options are given and time is limited.
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