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Average

Introduction to Average

In everyday life, we often want to summarize a collection of numbers by a single number that best represents them. This "middle value" or typical value is called Average. Imagine you have marks scored by five students in a test - instead of remembering all five scores, you can calculate their average to get a sense of their overall performance.

The average helps in understanding patterns and making comparisons. For example, you might want to know your average monthly expense, average speed during a trip, or average rainfall in a month. In all such scenarios, average tells us about the general trend of data rather than individual details.

Formally, average is a measure of central tendency, which means it indicates the center or typical value of a data set.

Arithmetic Mean

The most common type of average is the Arithmetic Mean. This is simply the sum of all values divided by the total number of values.

Mathematically, if you have numbers \( x_1, x_2, x_3, \ldots, x_n \), their arithmetic mean (average) is:

Arithmetic Mean

\[\text{Average} = \frac{\sum x_i}{n}\]

Sum of all values divided by number of values

\(x_i\) = Each value
n = Number of values

Example: Find the average of 4, 7, 10, 15, and 20.

  • Step 1: Add all numbers: \(4 + 7 + 10 + 15 + 20 = 56\)
  • Step 2: Count how many numbers: 5
  • Step 3: Divide the sum by count: \( \frac{56}{5} = 11.2 \)

So, the average is 11.2.

4 7 10 15 20 Sum (56) / Number of values (5) = 11.2

Weighted Average

Sometimes, certain values are more important or occur more frequently than others. In such cases, the simple average does not tell the whole story. Instead, we use a Weighted Average, where each value is multiplied by its weight or frequency before averaging.

For example, suppose a student scores 80 marks in a test worth 30% of the final grade, and 90 marks in a test worth 70%. The final average won't be simply the mean of 80 and 90, but weighted by the respective percentages.

The formula is:

Weighted Average

\[\text{Weighted Average} = \frac{\sum (w_i \times x_i)}{\sum w_i}\]

Sum of each value times its weight divided by sum of weights

\(w_i\) = Weight or frequency of ith value
\(x_i\) = Value itself

Consider the following table:

Value (Marks)Weight (Percentage %)Weighted Contribution
803080 x 30 = 2400
907090 x 70 = 6300
Total8700

Calculate weighted average:

\[\text{Weighted Average} = \frac{2400 + 6300}{30 + 70} = \frac{8700}{100} = 87\]

The final average score is 87, reflecting the importance of each test.

Effect of Adding or Removing Data Points

In exams and real scenarios, data sets can change. You may add new values or remove some. How does this affect the average?

Let's understand these effects using the total sum concept.

If the original average is \( \bar{x} \) with \( n \) values, then total sum is:

\[\text{Total Sum} = \bar{x} \times n\]

Now, if a new value \( a \) is added, the new average \( \bar{x}_{new} \) is:

Average after Adding New Data

\[\bar{x}_{new} = \frac{\bar{x} \times n + a}{n + 1}\]

Old total plus new value divided by old count plus one

\(\bar{x}\) = Old average
n = Old count
a = Added value

If a value \( r \) is removed, new average becomes:

Average after Removing Data

\[\bar{x}_{new} = \frac{\bar{x} \times n - r}{n - 1}\]

Old total minus removed value divided by old count minus one

\(\bar{x}\) = Old average
n = Old count
r = Removed value
graph TD  A[Start: Known Average and Count] --> B[Calculate total sum: Average x Count]  B --> C{Data Added or Removed?}  C -->|Added| D[New Total = Old Total + New Value]  C -->|Removed| E[New Total = Old Total - Removed Value]  D --> F[New Count = Old Count + 1]  E --> G[New Count = Old Count - 1]  F --> H[New Average = New Total / New Count]  G --> H  H --> I[End: Updated Average Known]

Summary

Key Concept

Understanding Average

Average is a central value representing a set of numbers, useful to summarize and compare data.

Formula Bank

Formula Bank

Arithmetic Mean
\[ \text{Average} = \frac{\text{Sum of all quantities}}{\text{Number of quantities}} \]
where: Sum of all quantities - total of all values; Number of quantities - count of values.
Weighted Average
\[ \text{Weighted Average} = \frac{\sum (w_i \times x_i)}{\sum w_i} \]
where: \(w_i\) - weight of ith quantity; \(x_i\) - value of ith quantity.
Average after Adding New Data
\[ \text{New Average} = \frac{(\text{Old Average} \times \text{Old Count}) + \text{New Value}}{\text{Old Count} + 1} \]
where: Old Average - original average; Old Count - original number of values; New Value - added data.
Average after Removing Data
\[ \text{New Average} = \frac{(\text{Old Average} \times \text{Old Count}) - \text{Removed Value}}{\text{Old Count} - 1} \]
where: Old Average - original average; Old Count - original number of values; Removed Value - data removed.
Average in Mixture Problems
\[ \text{Combined Average} = \frac{(\text{Average}_1 \times n_1) + (\text{Average}_2 \times n_2)}{n_1 + n_2} \]
where: Average_1, Average_2 - averages of groups; \(n_1\), \(n_2\) - counts of groups.

Worked Examples

Example 1: Calculate Average of Five Scores Easy
Find the average marks of a student who scored 65, 70, 75, 80, and 85 in five subjects.

Step 1: Add all marks: \(65 + 70 + 75 + 80 + 85 = 375\).

Step 2: Total number of subjects = 5.

Step 3: Use formula: Average = Sum / Number = \( \frac{375}{5} = 75 \).

Answer: The average marks scored by the student are 75.

Example 2: Weighted Average of Exam Scores Medium
A student scores 72 in an exam worth 40% of the final grade and 88 in another exam worth 60%. Find the final weighted average.

Step 1: Multiply scores by their weights:

  • 72 x 40 = 2880
  • 88 x 60 = 5280

Step 2: Add weighted scores: 2880 + 5280 = 8160.

Step 3: Add weights: 40 + 60 = 100.

Step 4: Calculate weighted average:

\[ \frac{8160}{100} = 81.6 \]

Answer: The final weighted average score is 81.6.

Example 3: Average After Adding a New Value Medium
The average daily production of a factory over 10 days is 500 units. On the 11th day, the factory produced 550 units. Find the new average production.

Step 1: Calculate total production for 10 days: \(500 \times 10 = 5000\) units.

Step 2: Add production of 11th day: \(5000 + 550 = 5550\) units in total.

Step 3: New count of days: 11.

Step 4: New average:

\[ \frac{5550}{11} = 504.55 \]

Answer: The new average production per day is approximately 504.55 units.

Example 4: Replacement in Data Set and New Average Hard
The average weight of 8 students is 55 kg. Two students leave the group and are replaced by two new students weighing 60 kg and 65 kg. The new average weight is 56.5 kg. Find the average weight of the two students who left.

Step 1: Calculate the total weight of original 8 students:

\(55 \times 8 = 440\) kg.

Step 2: Calculate the total weight of new group of 8 students:

New average x number = \(56.5 \times 8 = 452\) kg.

Step 3: Weight of new two students = \(60 + 65 = 125\) kg.

Step 4: Let the total weight of two students who left be \(w\).

Since replacing them causes the total to increase from 440 to 452,

New total = Old total - \(w\) + 125 = 452

\(440 - w + 125 = 452\)

\(565 - w = 452\)

\(w = 565 - 452 = 113\) kg.

Step 5: Average weight of two who left = \( \frac{113}{2} = 56.5 \) kg.

Answer: The average weight of the two students who left is 56.5 kg.

Example 5: Mixture of Two Groups Hard
Two classes have average marks of 70 and 80 respectively. The number of students in the first class is 30 and in the second class is 20. Find the combined average of both classes together.

Step 1: Calculate total marks of each class:

  • First class: \(70 \times 30 = 2100\) marks
  • Second class: \(80 \times 20 = 1600\) marks

Step 2: Add total marks: \(2100 + 1600 = 3700\) marks.

Step 3: Add total students: \(30 + 20 = 50\).

Step 4: Calculate combined average:

\[ \frac{3700}{50} = 74 \]

Answer: The combined average mark is 74.

Tips & Tricks

Tip: Multiply the average by the number of quantities to quickly get the total sum.

When to use: To avoid recalculating the sum from raw data, especially in replacement or addition problems.

Tip: Use weighted averages when different data points have different significance instead of just arithmetic mean.

When to use: When dealing with data sets with varying importance like marks with different max scores or stocks with different quantities.

Tip: When a new value is added or removed, manipulate the total sum instead of recalculating averages from scratch.

When to use: In problems asking for new averages after data changes.

Tip: In mixture problems, treat the combined data as weighted averages to find the combined mean quickly.

When to use: When combining two groups or sets with known averages and counts.

Tip: Practice eliminating unlikely options using approximate average estimates to save time during exams.

When to use: When multiple choice options are given and time is limited.

Common Mistakes to Avoid

❌ Dividing the sum by the wrong number of quantities.
✓ Ensure the denominator is exactly the count of all quantities included in the sum.
Why: Students often confuse total number of items with partial data points.
❌ Using simple average when weighted average is required.
✓ Identify presence of weights/frequencies and apply weighted average formula.
Why: Misunderstanding of problem context or overlooking differing importance of values.
❌ Forgetting to adjust count when values are added or removed before calculating new average.
✓ Always adjust the total count (denominator) accordingly.
Why: Focusing on values only causes denominator mistakes.
❌ Mixing up variables in mixture problems, e.g., swapping group sizes or averages.
✓ Carefully label each group's average and number before substitution.
Why: Complexity causes confusion without clear notation.
❌ Rounding intermediate results too early leading to inaccurate final averages.
✓ Keep intermediate steps precise and round off only at the final step.
Why: Loss of precision affects results, especially in decimal or large data sets.
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