When you hear the word average, it usually means finding a single value that best represents a group of numbers. Imagine you took five tests and want to know how you did overall. Instead of looking at all scores separately, you calculate the average score to find a typical or central value.
This "typical value" helps simplify complex data sets and allows easier comparison. For example, we often want to know the average temperature of a week or the average price of apples in a market.
There are two main types of averages we will explore:
Let's quickly think about daily life: if you scored 80% in Maths, 70% in Science, and 90% in English, finding the simple average gives your overall percentage. But what if Maths is twice as important as the other subjects? Then, we use the weighted average to emphasize Maths score more.
The average (also called arithmetic mean) of a set of numbers is found by adding all the numbers together and then dividing by how many numbers there are.
This is expressed by the formula:
\[ \text{Average} = \frac{\sum_{i=1}^n x_i}{n} \]
where \(x_i\) are the individual values and \(n\) is the number of values.
For example, if you have scores of 10, 15, 20, 25, and 30, you add all these (which equals 100) and divide by 5 (the number of scores), resulting in an average of 20.
| Data Points | Values |
|---|---|
| 1 | 10 |
| 2 | 15 |
| 3 | 20 |
| 4 | 25 |
| 5 | 30 |
| Sum | 100 |
| Count (n) | 5 |
| Average = Sum / Count | 100 / 5 = 20 |
Key points about averages:
In many practical cases, some values in data are more important or occur more frequently than others. This calls for the weighted average, where each value is multiplied by its weight, reflecting its importance or frequency.
The formula for weighted average is:
\[ \text{Weighted Average} = \frac{\sum_{i=1}^n w_i x_i}{\sum_{i=1}^n w_i} \]
where \(x_i\) are the values and \(w_i\) their corresponding weights.
For example, suppose a student has marks in subjects with different credit hours. The credit hours act as weights because subjects with more credit hours matter more for the overall grade.
Here, the height of each bar illustrates the weight (importance). Notice that the weighted average "leans" towards the values with greater heights/weights, adjusting the final average accordingly.
Step 1: Add all the marks: \(70 + 75 + 80 + 85 + 90 = 400\).
Step 2: Count the number of subjects: \(5\).
Step 3: Calculate average: \(\frac{400}{5} = 80\).
Answer: The average mark is 80.
Step 1: Multiply each price by the quantity (weight):
Step 2: Sum of prices weighted by quantities: \(Rs.120 + Rs.250 = Rs.370\).
Step 3: Total quantity: \(3 + 5 = 8 \text{ kg}\).
Step 4: Weighted average price: \(\frac{Rs.370}{8} = Rs.46.25 \text{ per kg}\).
Answer: The weighted average price is Rs.46.25 per kg.
Step 1: Multiply each grade by its credit:
Step 2: Sum weighted grades: \(27 + 32 + 14 = 73\).
Step 3: Sum credits: \(3 + 4 + 2 = 9\).
Step 4: GPA = \(\frac{73}{9} \approx 8.11\).
Answer: The weighted GPA is approximately 8.11.
Step 1: Calculate total distance: \(60 + 90 = 150 \text{ km}\).
Step 2: Calculate time for each segment:
Step 3: Total time = \(1.5 + 1.5 = 3 \text{ hours}\).
Step 4: Average speed = \(\frac{\text{Total Distance}}{\text{Total Time}} = \frac{150}{3} = 50 \text{ km/h}\).
Answer: The average speed is 50 km/h.
Step 1: Multiply each class's average marks by number of students (weights):
Step 2: Add total marks: \(3000 + 5100 = 8100\).
Step 3: Total students: \(40 + 60 = 100\).
Step 4: Weighted average marks = \(\frac{8100}{100} = 81\).
Answer: The combined average marks are 81.
When to use: Repeated values or data with different levels of importance
When to use: Weighted averages involving percentages or counts
When to use: Problems where speed changes over different distances
When to use: Any weighted average involving fractions or decimals
When to use: Situations where data points do not have equal significance
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