Imagine you lend your friend some money, say Rs.10,000. After some time, your friend returns the original money plus an extra amount as a thank you for lending it. This extra money is called interest.
In daily life, banks and financial institutions also lend money or accept deposits. Depending on the agreement, they pay or charge interest. When interest is calculated only on the original amount you lent or deposited (called the principal), it is known as simple interest.
Simple interest calculates money earned or owed based on the fixed principal amount, the rate of interest per year, and the duration for which the money is lent or borrowed. It does not include interest on any interest already earned.
Why use Simple Interest?
It is straightforward and easy to calculate, making it common in short-term loans, deposits, and many everyday financial problems.
We express simple interest mathematically using symbols:
The simple interest earned is directly proportional to principal, rate, and time. This means if any of these increase, the interest increases proportionally.
Putting these together, the formula is:
Let's understand why we divide by 100:
Since the rate is given as a percentage, 5% means 5 out of 100. Hence, multiplying P by R and T gives the product in terms of "percent-years," so dividing by 100 scales it correctly to rupees.
After earning simple interest, the total amount received or paid back is the sum of the original principal and the interest earned.
This is expressed as:
Where:
In other words, you get back the original money plus the interest for the time period.
| Time (years) | Principal (Rs.) | Interest (5% p.a.) (Rs.) | Total Amount (Rs.) |
|---|---|---|---|
| 1 | 10,000 | 500 | 10,500 |
| 2 | 10,000 | 1,000 | 11,000 |
| 3 | 10,000 | 1,500 | 11,500 |
Step 1: Identify values: \( P = 10,000 \), \( R = 5\% \), \( T = 2 \) years.
Step 2: Use formula \( SI = \frac{P \times R \times T}{100} \).
Step 3: Substitute values: \( SI = \frac{10,000 \times 5 \times 2}{100} = \frac{100,000}{100} = 1,000 \).
Answer: Simple interest earned is Rs.1,000.
Step 1: Given \( SI = 900 \), \( R=6\% \), \( T=3 \) years.
Step 2: Rearrange formula to find \( P \):
\( P = \frac{SI \times 100}{R \times T} \)
Step 3: Substitute values: \( P = \frac{900 \times 100}{6 \times 3} = \frac{90,000}{18} = 5,000 \).
Answer: The principal amount is Rs.5,000.
Step 1: Given \( SI = 2,400 \), \( P = 12,000 \), \( R = 8\% \).
Step 2: Rearrange formula to find \( T \):
\( T = \frac{SI \times 100}{P \times R} \)
Step 3: Substitute values: \( T = \frac{2,400 \times 100}{12,000 \times 8} = \frac{240,000}{96,000} = 2.5 \) years.
Answer: The time period is 2.5 years.
Step 1: Calculate SI for Rs.8,000 at 4% for 3 years:
\( SI_1 = \frac{8000 \times 4 \times 3}{100} = \frac{96,000}{100} = 960 \).
Total amount \( A_1 = 8000 + 960 = 8,960 \).
Step 2: Calculate SI for Rs.10,000 at 3% for 3 years:
\( SI_2 = \frac{10000 \times 3 \times 3}{100} = \frac{90,000}{100} = 900 \).
Total amount \( A_2 = 10,000 + 900 = 10,900 \).
Step 3: Compare amounts:
Rs.10,900 > Rs.8,960, so the Rs.10,000 deposit at 3% yields more total amount after 3 years.
Answer: Rs.10,900 and Rs.8,960 respectively; Rs.10,000 deposit returns more.
Step 1: Given \( P = 50,000 \), \( R = 8\% \), \( T = 1.5 \) years.
Step 2: Calculate simple interest:
\( SI = \frac{50,000 \times 8 \times 1.5}{100} = \frac{600,000}{100} = 6,000 \).
Step 3: Calculate total amount to repay:
\( A = P + SI = 50,000 + 6,000 = 56,000 \).
Answer: Total repayment is Rs.56,000 with interest Rs.6,000.
When to use: While performing stepwise multiplication and avoiding calculation errors.
When to use: Always check time units before solving.
When to use: To verify results and avoid silly mistakes.
When to use: Problems with missing values to find.
When to use: Speeding up calculations under exam time pressure.
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