Example 1: Basic Modulus Calculation (Easy)
Find the modulus of \( z = 3 + 4i \).
Solution:
\( |z| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5. \)
Answer: \( |z| = 5 \).
Introduction: The modulus of a complex number is a fundamental concept in algebra and complex number theory, crucial for understanding the magnitude or length of complex numbers in the Argand plane. This section covers the definition, properties, and applications of the modulus of complex numbers, with clear explanations and diagrams to build a strong conceptual foundation for NDA entrance exam preparation.
A complex number is generally expressed in the form:
\( z = x + iy \), where \( x, y \in \mathbb{R} \) and \( i = \sqrt{-1} \).
The modulus (or absolute value) of \( z \), denoted by \( |z| \), is defined as the distance of the point \( (x, y) \) from the origin \( (0,0) \) in the Cartesian plane (also called the Argand plane).
Mathematically,
\( |z| = \sqrt{x^2 + y^2} \).
Geometric Diagram:
In this diagram, the blue line represents the modulus \( |z| \), which is the hypotenuse of the right triangle formed by the real part \( x \) (horizontal green dashed line) and the imaginary part \( y \) (vertical green dashed line).
Given \( z = x + iy \), calculate modulus as:
\( |z| = \sqrt{x^2 + y^2} \).
A complex number can also be expressed in polar form:
\( z = r(\cos \theta + i \sin \theta) \), where \( r = |z| \) and \( \theta = \arg(z) \).
Here, the modulus \( |z| = r \) is the radius or distance from the origin.
Find the modulus of \( z = 3 + 4i \).
Solution:
\( |z| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5. \)
Answer: \( |z| = 5 \).
Given \( z_1 = 1 + i \) and \( z_2 = 2 - 2i \), find \( |z_1 z_2| \).
Solution:
Calculate \( |z_1| \) and \( |z_2| \):
\( |z_1| = \sqrt{1^2 + 1^2} = \sqrt{2} \),
\( |z_2| = \sqrt{2^2 + (-2)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}. \)
Using multiplicative property:
\( |z_1 z_2| = |z_1| \cdot |z_2| = \sqrt{2} \times 2\sqrt{2} = 2 \times 2 = 4. \)
Answer: \( |z_1 z_2| = 4 \).
Given \( z_1 = 3 + 4i \) and \( z_2 = 1 - 2i \), verify the triangle inequality \( |z_1 + z_2| \leq |z_1| + |z_2| \).
Solution:
Calculate \( z_1 + z_2 = (3 + 1) + (4 - 2)i = 4 + 2i \).
\( |z_1 + z_2| = \sqrt{4^2 + 2^2} = \sqrt{16 + 4} = \sqrt{20} = 2\sqrt{5}. \)
\( |z_1| = \sqrt{3^2 + 4^2} = 5, \quad |z_2| = \sqrt{1^2 + (-2)^2} = \sqrt{1 + 4} = \sqrt{5}. \)
Sum of moduli: \( 5 + \sqrt{5} \approx 5 + 2.236 = 7.236 \).
Since \( 2\sqrt{5} \approx 4.472 \leq 7.236 \), triangle inequality holds.
Answer: Verified \( |z_1 + z_2| \leq |z_1| + |z_2| \).
Find the distance between \( z_1 = 5 + 3i \) and \( z_2 = 1 + i \).
Solution:
Distance \( = |z_1 - z_2| = |(5 - 1) + (3 - 1)i| = |4 + 2i| = \sqrt{4^2 + 2^2} = \sqrt{16 + 4} = \sqrt{20} = 2\sqrt{5}. \)
Answer: Distance = \( 2\sqrt{5} \).
If \( z = 6(\cos 60^\circ + i \sin 60^\circ) \), find \( |z| \).
Solution:
In polar form, modulus \( |z| = r = 6 \).
Answer: \( |z| = 6 \).
Given \( z_1 = 7 + 24i \) and \( z_2 = 3 + 4i \), find the minimum value of \( |z_1 - z_2| \) using the reverse triangle inequality.
Solution:
Calculate \( |z_1| = \sqrt{7^2 + 24^2} = \sqrt{49 + 576} = \sqrt{625} = 25 \).
Calculate \( |z_2| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = 5 \).
Reverse triangle inequality states:
\[\big|,|z_1| - |z_2|,\big| \leq |z_1 - z_2|.\]
So, minimum \( |z_1 - z_2| \geq |25 - 5| = 20 \).
Answer: Minimum distance \( |z_1 - z_2| \) is 20.
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